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3.5.2 DG for the acoustic wave equation

We consider the acoustic problem \begin{align} \partial_{t} \mathbf{u} - c \nabla p &= 0 \quad \text{ in } \Omega \times I, \\ \partial_{t} p - c \operatorname{div}(\mathbf{u}) &= 0 \quad \text{ in } \Omega \times I, \\ % p (0,\cdot) &= p(1,\cdot), \quad % p (\cdot,0) = p(\cdot,1), \label{eq:per2b}\\ % \mathbf{q} (0,\cdot) &= \mathbf{q}(1,\cdot), \quad % \mathbf{q} (\cdot,0) = \mathbf{q}(\cdot,1), \label{eq:per2bb}\\ p &= p_0 \!\!\! \quad \text{ on } \Omega \times \{0\},\\ u &= 0 \quad \text{ on } \Omega \times \{0\}. \end{align}

Here \(p\) is the acoustic pressure (the local deviation from the ambient pressure) and \(\mathbf{u}\) is the local velocity.

+ suitable boundary conditions

A simple grid:

[1]:

#imports, geometry and mesh:
from netgen.occ import *
from netgen.webgui import Draw as DrawGeo
geo = OCCGeometry(unit_square_shape.Scale((0,0,0),2).Move((-1,-1,0)), dim=2)
from ngsolve import *
from ngsolve.webgui import Draw
mesh = Mesh(geo.GenerateMesh(maxh=0.1))
Draw(mesh)

[1]:

BaseWebGuiScene

Find \(p: [0,T] \to \bigoplus_{T\in\mathcal{T}_h} \mathcal{P}^{k+1}(T)\) and \(\mathbf{u}: [0,T] \to \bigoplus_{T\in\mathcal{T}_h} [\mathcal{P}^k(T)]^d\) so that

\begin{align*} (\partial_t \mathbf{u}, v) &= b_h(p,v) & &&& \forall v,\\ (\partial_t p, q) &= & - b_h(q,\mathbf{u}) &&& \forall q\\ \end{align*}

with the centered flux approximation:

\[b_h(p,v) = \sum_{T} \int_T \nabla p \cdot v + \int_{\partial T} ( \hat{p} - p) v_n\]

Here \(\hat{p}\) is the centered approximation i.e. \(\hat{p} = \{\!\!\{p\}\!\!\}\).

[2]:

order = 6
fes_p = L2(mesh, order=order+1, all_dofs_together=True)
fes_u = VectorL2(mesh, order=order, piola=True, all_dofs_together=True)
fes = fes_p*fes_u
gfu = GridFunction(fes)

What is the flag piola doing?

The VectorL2 space uses the following definition of basis functions on the mesh.

Let \(\hat{\varphi}(\hat{x})\) be a (vectorial) basis function on the reference element \(\hat{T}\), \(\Phi: \hat{T} \to T\) with \(x = \Phi(\hat{x})\) and \(F= D\Phi\), then

\[\begin{split}\varphi(x) := \left\{ \begin{array}{rlll} \hat{\varphi}(\hat{x}), & \texttt{piola=False}, & \texttt{covariant=False}, & \text{(default)} \\ \frac{1}{|\operatorname{det} F|} \cdot F \cdot \hat{\varphi}(\hat{x}), & \texttt{piola=True}, & \texttt{covariant=False}, \\ F^{-T} \cdot \hat{\varphi}(\hat{x}), & \texttt{piola=False}, & \texttt{covariant=True}. \\ \end{array} \right.\end{split}\]

Inverse mass matrix operations:

Combining Embedding and the inverse mass matrix operation for fes_p allows to realize the following block inverse operations acting on fes:

\[\begin{split}\underbrace{\left( \begin{array}{cc} M_{p}^{-1} & 0 \\ 0 & 0 \end{array} \right)}_{\texttt{invp}} = \underbrace{\left( \begin{array}{c} I \\ 0 \end{array} \right)}_{\texttt{emb_p}} \cdot \underbrace{M_{p}^{-1}}_{\texttt{invmassp}} \cdot \underbrace{\left( \begin{array}{cc} I & 0 \end{array} \right)}_{\texttt{emb_p.T}}\end{split}\]
[3]:

pdofs = fes.Range(0);
emb_p = Embedding(fes.ndof, pdofs)
invmassp = fes_p.Mass(1).Inverse()
invp = emb_p @ invmassp @ emb_p.T

Analogously, combining Embedding and the inverse mass matrix operation for fes_u allows to realize the following block inverse operations on fes:

\[\begin{split}\underbrace{\left( \begin{array}{cc} 0 & 0 \\ 0 & M_{\mathbf{u}}^{-1} \end{array} \right)}_{\texttt{invu}} = \underbrace{\left( \begin{array}{c} I \\ 0 \end{array} \right)}_{\texttt{emb_u}} \cdot \underbrace{M_{\mathbf{u}}^{-1}}_{\texttt{invmassu}} \cdot \underbrace{\left( \begin{array}{cc} I & 0 \end{array} \right)}_{\texttt{emb_u.T}}\end{split}\]
[4]:

udofs = fes.Range(1)
emb_u = Embedding(fes.ndof, udofs)
invmassu = fes_u.Mass(Id(mesh.dim)).Inverse()
invu = emb_u @ invmassu @ emb_u.T

Time loop

Assuming the operators B,BT: fes_p\(\times\) fes_u \(\to\)(fes_p\(\times\) fes_u )\('\) corresponding to \(B_h((u,p),(v,q)=b_h(p,v)\) are given, the symplectic Euler time stepping method takes the form:

[5]:

def Run(B, BT, t0 = 0, tend = 0.25, tau = 1e-3,
        backward = False, scenes = []):
    t = 0
    with TaskManager():
        while t < (tend-t0) - tau/2:
            t += tau
            if not backward:
                gfu.vec.data += -tau * invp @ BT * gfu.vec
                gfu.vec.data += tau * invu @ B * gfu.vec
                print("\r t = {:}".format(t0 + t),end="")
            else:
                gfu.vec.data += -tau * invu @ B * gfu.vec
                gfu.vec.data += tau * invp @ BT * gfu.vec
                print("\r t = {:}".format(tend - t),end="")
            for sc in scenes: sc.Redraw() # blocking=False)
        print("")

Initial values (density ring):

[6]:

gfu.components[0].Set (exp(-50*(x**2+y**2))-exp(-100*(x**2+y**2)))
gfu.components[1].vec[:] = 0
Draw(gfu.components[0], mesh, "p", min=-0.02, max=0.08, autoscale=False, order=3)

[6]:

BaseWebGuiScene

Version 1:

The bilinear form for application on the full space fes

[7]:

n = specialcf.normal(mesh.dim)
(p,u),(q,v) = fes.TnT()
B = BilinearForm(fes, nonassemble=True)
B += grad(p)*v * dx + 0.5*(p.Other()-p)*(v*n) * dx(element_boundary=True)
BT = BilinearForm(fes, nonassemble=True)
BT += grad(q)*u * dx + 0.5*(q.Other()-q)*(u*n) * dx(element_boundary=True)

[8]:

scenep=Draw(gfu.components[0], mesh, "p", min=-0.02, max=0.08,
            autoscale=False, order=3, deformation=True)
%time Run(B.mat, BT.mat, backward=False, scenes=[scenep])
%time Run(B.mat, BT.mat, backward=True, scenes=[scenep])

 t = 0.25000000000000017
CPU times: user 15 s, sys: 155 ms, total: 15.2 s
Wall time: 3.8 s
 t = -1.6653345369377348e-16
CPU times: user 14.9 s, sys: 177 ms, total: 15 s
Wall time: 3.76 s

Version 2:

Using the TraceOperator and assembling of \(b_h\)

We want to use the TraceOperator again:

[9]:

fes_tr = FacetFESpace(mesh, order=order+1)
traceop = fes_p.TraceOperator(fes_tr, False)

We want to assemble the sub-block matrix and need test/trial functions for single spaces (not the product spaces):

[10]:

p = fes_p.TrialFunction()
v = fes_u.TestFunction()
phat = fes_tr.TrialFunction()

We split the operator to \(b_h\) into * volume contributions (local) * and couplings between the trace (obtained through the trace op) and the volume:

[11]:

Bel = BilinearForm(trialspace=fes_p, testspace=fes_u)
Bel += grad(p)*v * dx -p*(v*n) * dx(element_boundary=True)
%time Bel.Assemble()

Btr = BilinearForm(trialspace=fes_tr, testspace=fes_u)
Btr += 0.5 * phat * (v*n) * dx(element_boundary=True)
%time Btr.Assemble()

B = emb_u @ (Bel.mat + Btr.mat @ traceop) @ emb_p.T

CPU times: user 114 ms, sys: 24.1 ms, total: 138 ms
Wall time: 137 ms
CPU times: user 38.8 ms, sys: 15.9 ms, total: 54.7 ms
Wall time: 54.5 ms

Version 2 in action (assembled matrices, TraceOperators and Embeddings can do transposed multiply):

[12]:

%time Run(B, B.T, backward=False)
%time Run(B, B.T, backward=True)

 t = 0.25000000000000017
CPU times: user 12.5 s, sys: 5.29 s, total: 17.7 s
Wall time: 4.44 s
 t = -1.6653345369377348e-16
CPU times: user 12.5 s, sys: 5.19 s, total: 17.7 s
Wall time: 4.44 s

Version 3:

Using the TraceOperator and geom_free=True with assembling

With \(p(x) = \hat{p}(\hat{x})\) and \(\mathbf{v}(x) = \frac{1}{|\operatorname{det}(F)|} F \cdot \hat{\mathbf{v}}(\hat{x})\) (Piola mapped) there holds

\begin{align} \int_T \mathbf{v} \cdot \nabla p = \int_{\hat{T}} \hat{\mathbf{v}} \cdot \hat{\nabla} \hat{p} \end{align}

and similarly for the facet integrals, cf. unit-2.11 and

Integrals are independent of the "physical element" (up to ordering)

\(\leadsto\) same element matrices for a large class of elements

[13]:

Bel = BilinearForm(trialspace=fes_p, testspace=fes_u, geom_free = True)
Bel += grad(p)*v * dx -p*(v*n) * dx(element_boundary=True)
%time Bel.Assemble()

Btr = BilinearForm(trialspace=fes_tr, testspace=fes_u, geom_free = True)
Btr += 0.5 * phat * (v*n) *dx(element_boundary=True)
%time Btr.Assemble()

B = emb_u @ (Bel.mat + Btr.mat @ traceop) @ emb_p.T

CPU times: user 2.13 ms, sys: 0 ns, total: 2.13 ms
Wall time: 1.41 ms
CPU times: user 1.63 ms, sys: 220 μs, total: 1.85 ms
Wall time: 1.63 ms

Version 3 in action:

[14]:

%time Run(B, B.T, backward=False)
%time Run(B, B.T, backward=True)

 t = 0.25000000000000017
CPU times: user 3.14 s, sys: 154 ms, total: 3.3 s
Wall time: 824 ms
 t = -1.6653345369377348e-16
CPU times: user 3.22 s, sys: 78.1 ms, total: 3.29 s
Wall time: 823 ms

References: